Share Button In this video, Michael Shackleford, who is also known as the “Wizard of Odds,” explains all about Ultimate Texas Hold’em. …

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  • Russell Warren 4 years ago

    Here’s the problem I see with the basic strategy. It doesn’t take into
    account “pot odds”. Instead it goes by expected value. If positive bet
    4X. However, if you win 51% of the time but lay 2:1 odds (4 X ante, which
    is =blind, or 2:1), you will lose long term (besides the house edge). In
    order to raise 4X you should only play hands >.67 probability of winning
    against unknown cards. I used win percentages from For hands
    between .6 and .67, one should bet 3X, or 3:2 odds. This will maximize
    wins while minimizing variances. AK can be beat by a pair of 2s, so why
    lay 2:1 odds when only 64% chance of winning. If you play 3X you are
    getting better than pot odds for winning that hand. In other words instead
    of laying an extra 2.5% to the house edge, you reduce it by more than 4% on
    this one hand. In other words by using this strategy, one could
    theoretically shift house edge to player edge when playing hands from
    .51-.667 expected value. Raise 4X for all pairs >8s; 3X for pocket 6s, 7s,
    >A9s, >KQ. All other hands have less than .60 probability of winning, so
    should not raise before flop. Heads up Pocket 4s win 56% so raising 2X
    after flop creates positive pot odds that again erode some of the house
    edge. One can even wait until after river to call. One loses value in
    winning, but decreases variances of losses. True, for the most part, one
    may win less, there will be less variance (for smaller bankrolls). The
    value of a hand changes greatly after the flop. A flop of overs with
    possible flush/straight draws (i.e. 7/8/10 flop while holding pocket
    5s)loses value quickly and may even prevent a 2X bet on the flop.

    For example, let’s use 44 (which has roughly a 6/11 chance of winning).
    First the basic strategy: Over 11 hands, you will win 6 hands at 5 units
    and lose 6 units 5 times, and break even with -30/+30. Now using my
    strategy for the same; (assuming I only raise 2X with favorable flop), I
    will lose 3 units 5 times and win 3 units 6 times. As long as I win and
    dealer qualifies >3 times, I will come out ahead. I admit, I know I think
    more as I am a poker player and know the probability of wining various
    hands. For those plying for fun, my play may not be for them. 

  • anthony seak 4 years ago

    I have a question.. can you get up and leave at anytime when you play hold
    em at a casino? 

  • John Smith 4 years ago

    3:40 Now that you’re confused by this game because we went so fast, we’re
    gonna flip the image to further disorient you.

  • Raymond Olivas 4 years ago

    Are you able to give me another example of outs when it comes to this game?

    I am sorry to day but the example the wizard gives is still confusing me?

    For each rank on the board there are three more that can beat you. For
    example, if the dealer has the jack of hearts, diamonds, or spades he will
    pair up and beat you. So, 5×3=15 cards will give the dealer a hidden pair.
    Also, all four queens and aces will beat you. So, 15+8=23 cards will beat
    you. You need to have less than 21 outs to stay in, so fold.

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